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- From: "joe (j.) halpin" <jhalpin@bnr.ca>
- Message-ID: <4iss70$82f@crchh327.rich.bnr.ca>
- X-Original-Date: Fri, 22 Mar 1996 00:28:16 +0000
- Path: in2.uu.net!bounce-back
- Date: 22 Mar 96 02:02:01 GMT
- Approved: fjh@cs.mu.oz.au
- Subject: Re: Referencing pointers after delete
- Newsgroups: comp.std.c++
- Organization: Bell-Northern Research, Richardson, TX
- X-Auth: PGPMoose V1.1 PGP comp.std.c++
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- =de/9
-
- In article <4isca2$t20@news.BelWue.DE>,
- Dietmar Kuehl <dietmar.kuehl@uni-konstanz.de> wrote:
- >Hi,
- >
- >joe (j.) halpin (jhalpin@bnr.ca) wrote:
- >: In 3.7.3.2.4 the January working paper says:
- >
- >: 4 A deallocation function can free the storage referenced by the pointer
- >: given as its argument and renders the pointer invalid. The storage
- >: can be made available for further allocation. An invalid pointer con-
- >: tains an unusable value: it cannot even be used in an expression.
- >
- >: This sounds as though, in the following:
- >
- >: char *pc = new char[128];
- >: delete pc;
- >: pc = 0;
- >
- >: it makes the final assignment (an expression) invalid.
- >
- >No. You cannot use the value of the pointer but you can use the pointer
-
- So, in the sentence above - "An invalid pointer contains an unusable
- value: it cannot even be used in an expression." - the word 'it'
- refers to the value and not the pointer? That makes sense, although
- the phrasing is a bit ambiguous.
-
- >(actually, you get undefined behavior in the code above because you
- >delete an array object with 'delete' instead of 'delete[]'; I assume
-
- Mea culpa.
-
- [...]
-
- Thanks
-
- Joe
- --
- Joe Halpin jhalpin@nortel.com
- Nortel Wireless (214) 684-5657
- Richardson, TX 75083-3871 <standard disclaimer applies>
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